How do you get 0.501 M with 41.0 mL and 3.41M and 279mL
Using formula of resultant molality-
m=m1v1+m2v2v1+v2m=\dfrac{m_1v_1+m_2v_2}{v_1+v_2}m=v1+v2m1v1+m2v2
=0.501×41+3.41×27941+279=971.931320=3.07M=\dfrac{0.501\times 41+3.41\times 279}{41+279}\\[9pt]=\dfrac{971.931}{320}=3.07M=41+2790.501×41+3.41×279=320971.931=3.07M
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