Question

How many grams of water are produced if 33.0 grams of N2O is produced?

Answer 1

Moles of $N_2O$ = $given \ mass \over molar \ mass$

=${0.33\over 44 } = {3\over 4}mole$

Balanced equation

$NH_4NO_3(s) \rightarrow N_2O(g) + 2H_2O(l)$

We can see that 1 mole $NH_4NO_3$ Produce 1 mole $N_2O$ and 2 mole $H_2O$

So ${3\over 4}$ mole $NH_4NO_3$ Produce ${3\over 4}$ mole $N_2O$ and ${6\over 4}$ mole $H_2O$

Mass of $H_2O$ = moles × molar mass

= ${6\over 4}×18 \ g$

Answer = $\boxed{27 g}$