How many grams of water are produced if 33.0 grams of N2O is produced?
Moles of "N_2O" = "given \\ mass \\over molar \\ mass"
="{0.33\\over 44 } = {3\\over 4}mole"
Balanced equation
"NH_4NO_3(s) \\rightarrow N_2O(g) + 2H_2O(l)"
We can see that 1 mole "NH_4NO_3" Produce 1 mole "N_2O" and 2 mole "H_2O"
So "{3\\over 4}" mole "NH_4NO_3" Produce "{3\\over 4}" mole "N_2O" and "{6\\over 4}" mole "H_2O"
Mass of "H_2O" = moles × molar mass
= "{6\\over 4}\u00d718 \\ g"
Answer = "\\boxed{27 g}"
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