The vapor pressure of water at 80°C is 0.4675 atm. Calculate the vapor pressure in kPa. Be sure your answer has the right number of significant digits.
0.4675 atm=0.4675×(1 atm)0.4675\ atm= 0.4675\times (1\ atm)0.4675 atm=0.4675×(1 atm)
0.4675 atm=0.4675×(1.01325 bar)0.4675\ atm= 0.4675\times (1.01325\ bar)0.4675 atm=0.4675×(1.01325 bar)
0.4675 atm≈0.4737 bar0.4675\ atm\approx \boldsymbol{0.4737\ bar}0.4675 atm≈0.4737 bar
And,
0.4675 atm=0.4737×(1 bar)0.4675\ atm=0.4737\times (1\ bar)0.4675 atm=0.4737×(1 bar)
0.4675 atm=0.4737×(105 Pa)0.4675\ atm=0.4737\times (10^5\ Pa)0.4675 atm=0.4737×(105 Pa)
0.4675 atm=47.37 kPa0.4675\ atm=\boldsymbol{47.37\ kPa}0.4675 atm=47.37 kPa
=47.37 kPa
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