What is the pOH of a solution containing an [H+] concentration of 2.75*10-3?
pH=−log[H+]=−log(2.75×10−3)=2.561pH=-log[H^+]=-log(2.75\times10^{-3})=2.561pH=−log[H+]=−log(2.75×10−3)=2.561
pOH=14−pH=14−2.561=11.439pOH=14-pH=14-2.561=11.439pOH=14−pH=14−2.561=11.439
Answer: 11.439
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