Question #189233

What is the pOH of a solution containing an [H+] concentration of 2.75*10-3? 


1
Expert's answer
2021-05-05T01:41:58-0400

pH=−log[H+]=−log(2.75×10−3)=2.561pH=-log[H^+]=-log(2.75\times10^{-3})=2.561

pOH=14−pH=14−2.561=11.439pOH=14-pH=14-2.561=11.439


Answer: 11.439


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Place free inquiry
Calculate the price
Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!
Our fields of expertise
Submit Your Assignment. We Can Do It.
LATEST TUTORIALS
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult. You can find this expert in "Assignmentexpert.com" with confidence. Exceptional experts! I appreciate your help. God bless you!
Canada #340153 on Dec 2023