Calculate the mass of water formed when 4.6 g of oxygen gas reacts with excess hydrogen gas.
2H2+O2>2H2O
balanced equation
"2H_2+O_2>2H_2O"
Moles of oxygen = "given \\ mass \\over {molar \\ mass}"
"={4.6 g\\over 32 g}"
= 0.14 mole
2 moles O2 gives 2 mole of H2O
0.14 mole O2 will give 0.14 mole of H2O
Mass of H2O = moles × molar mass
= 0.14×18
"= 2.52 g" answer
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