Answer to Question #188889 in General Chemistry for MADHURA

Question #188889

calculate the molar volume of argon at 100'C and 100 atm on the assumption that it is a van der Waals gas


1
Expert's answer
2021-05-04T14:20:41-0400

Molar volume is the volume occupied by one mole of gas at room temperature and pressure

PV=nRT

P = pressure = 100 atm

V= volume of gas

n= 1 mole

R= 0.82057 l atm mol1 k1l\ atm\ mol^{-1}\ k^{-1}

T= Temperature =100o C100^{o}\ C =100o C +273.15=373.15 K100^{o}\ C\ +273.15=373.15\ K

PV=nRT , Now deviding by volume on both side of the equation


V = nRTP\dfrac{nRT}{P}..........1) , we know that N=mM\dfrac{m}{M} ,m = mass of gas , M = molar mass of gas

In equation .....1) , multiplying by molar mass of gas to both side of equation .


V=nRTP=1×0.82057×373.15100=3.0619 L\dfrac{nRT}{P}=\dfrac{1\times 0.82057\times373.15}{100}=3.0619\ L

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