Question

How many grams of NaAlO2 is produced if 126.4 g of NaOH reacts completely

Answer 1

$2Al+2NaOH+2H_2O→2NaAlO_2+3H_2$

$Molar Mass of 2NaAlO_2=(2×23)+(2×27)+(2×48)$

=196g/mol=196g/mol

Moles=Mass/Molar MassMoles=Mass/MolarMass

=126.4g/196g/mol

=0.748Mol NaAlO2