How many grams of NaAlO2 is produced if 126.4 g of NaOH reacts completely
"2Al+2NaOH+2H_2O\u21922NaAlO_2+3H_2"
"Molar Mass of 2NaAlO_2=(2\u00d723)+(2\u00d727)+(2\u00d748)"
=196g/mol=196g/mol
Moles=Mass/Molar MassMoles=Mass/MolarMass
=126.4g/196g/mol
=0.748Mol NaAlO2
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