Question

Calculate the molecular formula of an organic compound containing 72.31% carbon and 7.69% hydrogen by mass if it's relative molar mass is 78. (C=12,H=1)

Answer 1

Moles of C $= \frac{72.31}{12}=6.03moles$

Mole of H $= \frac{7.69}{1}= 7.69moles$

Molecular formula = $C_6H_{8}$