calculate the molar volume of argon at 100'C and 100 atm on the assumption that it is a van der waals gas
So molar volume is the volume of 1 mole. here's the Van der Waals equation
(P + an²/V²) x (V - nb) = nRT
V - Pnb + an²/V - an³b/V² = nRT
PV - Pnb + an²/V - an³b/V² - nRT = 0
multiply through by V²
(P)V³ + (-Pnb - nRT)V² + (an²)V - an³b = 0
P = 100 atm
T = 373.15 K
n = 1 mole
a = 1.355 L²bar/mol² x (1atm / 1.01325bar) = 1.337 L²atm/mol²
b = 0.03201 L/mol
(100 atm) * V³ + (-33.82 Latm) * V² + (1.337 L²atm) * V - (0.04280 L³atm) = 0
100V³ - 33.82V² + 1.337V - 0.04280 = 0
V/n = 0.299 L/mol
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