1.20g Sb reacts with 2.40g of I 2 :
2Sb + 3I2 → 2SbI3
Mole ratio 2:3 which implies 2 mols of Sb reacts with 3 moles of I to yield 2 moles of SbI3.
1.2+ 2.4= 3.6g of SbI3 produced
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