Question

Determine the mass of PbCrO₄  are produced when 0.25mol of K₂CrO₄

K₂CrO₄ + Pb(NO)₃ →   PbCrO₄ + 2KNO₃

(molar mass of  PbCrO₄= 323g/mol)

Answer 1

the reaction should be as follows

$K_2CrO_4 + Pb(NO_3)_2 → PbCrO_4 + 2KNO_3$

now given moles of  K₂CrO₄ is 0.25

by stoichiometry moles of  PbCrO₄ is 0.25 moles

mass = moles $\times$ molar mass

= 0.25$mole\times 323g/mole$

$\boxed{mass = 80.75 g } \ answer$