Question

If the [OH^ - ] of a solution is 2.46 * 10 ^ - 2 * M , what is the pH of the solution ?

Answer 1

Concentration of $[OH^{-}]=2.46\times10^{-2}\space M$

$p[OH^-]=-log(2.46\times10^{-2})=1.60$

$p[H]+p[OH^-]=14$

$p[H]=14-1.60=12.4$