Answer to Question #187390 in General Chemistry for Joanna Mar

Question

97.5mL of gas is collected over water at 300C and 785mmHg. What is the pressure of the dry gas at 25.0C in a 105mL container?

Answer 1

$\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}$

$\frac{785×97.5}{573}= \frac{P_2×105}{298}$

$P_2= 379.09 mmHg$