97.5mL of gas is collected over water at 300C and 785mmHg. What is the pressure of the dry gas at 25.0C in a 105mL container?
"\\frac{P_1V_1}{T_1}= \\frac{P_2V_2}{T_2}"
"\\frac{785\u00d797.5}{573}= \\frac{P_2\u00d7105}{298}"
"P_2= 379.09 mmHg"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment