Question

unbalanced

NH₃ + HOCl → NCl₃ + H₂O

If 40.5 grams of HOCl react with an excess of NH₃ how many moles of NCl₃ will form? 

Answer 1

NCl₃ + 3H₂O → NH₃ + 3HOCl

Moles of HOCL = $\frac{40.5}{52.46}=0.77mol$

Moles of NCl3 = $\frac{0.77}{3}=0.26mol$