unbalanced
NH3 + HOCl → NCl3 + H2O
If 40.5 grams of HOCl react with an excess of NH3 how many moles of NCl3 will form?
NCl3 + 3H2O → NH3 + 3HOCl
Moles of HOCL = "\\frac{40.5}{52.46}=0.77mol"
Moles of NCl3 = "\\frac{0.77}{3}=0.26mol"
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