enthalpy change of Cl2 + 2HBr —> 2HCl + Br2
∆°fHBr= -36.2KJ/mol
∆°fHCl= -92.3KJ/Mol
∆H = Hproducts - Hreactants
∆H= [2(-92.3) - 2(-36.2)]
∆H= -184.6 + 72.4
∆H= -122.2KJ/mol
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