Question #187284

If you used 10 mL of each solution to make your reaction between Na2CO3 (aq) and Co (NO3) 2 (aq), calculate the amount of precipitate, in grams. The concentrations are both 0.1 M


1
Expert's answer
2021-05-03T07:56:03-0400

Moles=0.1×101000=1.0×103Moles = 0.1×\frac {10}{1000}= 1.0×10^{-3}


Mass=1.0×103×182=0.182gramsMass = 1.0×10^{-3}× 182 =0.182 grams



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