Question

Find the mass of the nonelectrolyte X (MW=142 g/mol) required to make 250 mL of a solution having an osmotic pressure of 600 mmHg at 25°C.

a. 12.4 g

b. 10.3 g

c. 1.15 g

d. 115 g

Answer 1

PV = nRT

$600×250=n(62.363×298)$

$n= 8.071 moles$

$Mass= 142×8.071=1146.13$ or $1.15grams$