Question

If a gas is at 220K in a 55L container with a pressure of 2.2 atm, then what is the new temperature if the pressure increases to 3.3 atm and the volume decreases to 32.9 L?

Answer 1

$T_2=\frac{220×3.3×32.9}{2.2×55}$

$T_2=197.4K$