Question

What is the molality of a solution dissolved in chloroform that boils at 62.8℃? 

Boiling point of chloroform is 61.2℃? 𝐾𝐵 of chloroform is 3.63℃/𝑚

Answer 1

$ΔT b ​ =(62.8 ° C−61.2 ° C)=1.6 ° C\\ K_ b ​ =3.63 ° C/mol\\ ΔT=K b ​ .m$

$m =\dfrac{∆T}{K_b} = \dfrac{1.6}{3.63} = 0.45$ mol/kg