2C5H11OH+O2 to give CO2 +H2O. How many moles of O2 are needed for combustion of 1 mole of alkanol
The equation for the reaction is;
2C5H11OH+15O2→10CO2+12H2O2C_5H_{11}OH+15O_2\to 10CO_2+12H_2O2C5H11OH+15O2→10CO2+12H2O
Mole ratio of Pentanol to Oxygen =2:15=2:15=2:15
Moles of Oxygen=15×1mole2=15\times1mole\over22=15×1mole =7.5molesO2=7.5 moles O_2=7.5molesO2
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