Question

1.  a)What volume of 6.0 mol/L hydrochloric acid would be diluted with water to prepare 1.0 L of 1.2 mol/L hydrochloric acid?

Answer 1

$Moles (HCL) =1.0×1.2=1.2moles$

$Volume=\frac{1.2}{6.0}=0.2L$ or $200ml$