Question #186064

2s + 3O2 __> 2SO3


1
Expert's answer
2021-04-27T07:48:19-0400

ΔH3final=2(ΔH2)+ΔH1ΔH_3final = -2 (Δ H_2 ) + ΔH_1


=2×297+(790)=196KJ=-2 × -297 + (-790 ) = -196 KJ


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