2s + 3O2 __> 2SO3
ΔH3final=−2(ΔH2)+ΔH1ΔH_3final = -2 (Δ H_2 ) + ΔH_1ΔH3final=−2(ΔH2)+ΔH1
=−2×−297+(−790)=−196KJ=-2 × -297 + (-790 ) = -196 KJ=−2×−297+(−790)=−196KJ
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