Question #185402

If 0.100 mole of NH3 is added to 1.00 L of 2.00 x 10-2 M solution of M2+, giving [M(NH3)6]2+and a free M2+ concentration of 0.001, what is pKf for [M(NH3)6]2+?



1
Expert's answer
2021-04-25T23:15:39-0400

pKf for [M(NH3)6]2+[M(NH3)6]^{2+} =−7.8808-7.8808


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