Calculate the total mass, in grams of precipitate produced when 10.0 ml of 2.50 M SrS (aq) reacts completely with ZnSO4 (aq).
SrS + ZnSO4 --> ZnS + SrSO4
Molar Mass of SrS = 119.68
= 119.68 × 2.5/10 = 29.92g
Molar Mass of ZnSO4 = 161.47g
= 161.47 × 2.5/10 = 40.3675g
= 29.92 + 40.3675
= 70.2875g
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