A sample of nitrogen gas collected at a pressure of 1.16 atm and a temperature of 29.0 °C is found to occupy a volume of 20.9 liters. How many moles of N2 gas are in the sample____  mol
Here we will apply the Ideal Gas Law;
PV=nRT
Solving for n we have;
"n=\\dfrac{PV}{RT}"
P = 1.16 atm
V = 20.9 L
T = (29.0 oC + 273) = 302 K
Since P is in atm we use R = 0.03205 L*atm*mol-1*K-1
Therefore;
"n=\\dfrac{1.16atm x 20.9L}{0.03205Latmmol^-1K^-1x302K} = 2.505 mol"
Moles of N2 in the sample is 2.505 mol
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