Calculate the molality of a 100g table sugar (C12H22O11) with a molar mass of 342.3g/mol placed in 350g of H2O
n(Sugar)=n(Sugar)=n(Sugar)= mMm\over MMm =350342.3=350\over 342.3342.3=350 =1.022mol=1.022mol=1.022mol
Molarity=Molarity=Molarity= MolesofsoluteLiterofsolutionMoles of solute\over Liter of solutionLiterofsolutionMolesofsolute
=1.0220.1=1.022\over 0.10.1=1.022 =10.22mol/L=10.22mol/L=10.22mol/L
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