Answer to Question #184829 in General Chemistry for Ayame

Question

In the reaction 3 MgCl₂+ 2 K₃PO₄ to Mg₃(PO₄)₂ + 6 KCl, how many moles of KCI will form if 4.0 moles of K₃PO₄ react?

Answer 1

Mole ratio = 2:6

2 moles of  K₃PO₄ reacts to produce 6 moles of KCL therefore moles of KCL produce is 4×(6÷2) = 12 moles

12 moles of KCL are produced