Answer to Question #184492 in General Chemistry for Tzuyu

Question

Consider the reaction between 60.0 ml of liquid methyl alcohol, CH3OH (density = .850 g/ml) and 30.1 liters of O2 at 27°C and a pressure of 1.5 atm. The products of the reaction are CO2(g) and H2O(g). Calculate the number of grams of CO2 formed if the reaction goes to completion. The balanced equation is: 2CH3OH + 3O2 ------> 2CO2 + 4H2O

Answer 1

Mass of methyl alcohol = 60 × 0.850 = 51g

Mole= mass/molar mass = 51/32 = 1.59mole

Mole of O2 = PV/RT = 1.5 ×30.1 /(0.082 × 300)

= 1.84 mol

By the balanced equation, the limiting reagent is O2

3O₂ = 2CO₂ = 2 × 44g CO₂

3 mole = 88g CO₂

1.84 mole = 88 × 1.84 / 3

= 53.97g CO₂