In order to depress the freezing point of water to -12°C, how much magnesium nitrate would you have to add to 500g of water?
∆Tf=Ti−Tfsol∆T_f=T_i-T_{fsol}∆Tf=Ti−Tfsol
∆Tf=0−−12=12°c∆T_f=0--12=12°c∆Tf=0−−12=12°c
The cryoscopic constant of water is equal to 1.86°C1.86°C1.86°C kg/mol−1kg/mol^{-1}kg/mol−1
van't Hoff factor, of magnesium nitrate is 222
Molarity=122×1.86=3.23mol/kgMolarity =\frac{12}{2×1.86}=3.23 mol/kgMolarity=2×1.8612=3.23mol/kg
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