Question

Given the following equation:

 Al2(SO3)3 + 6 NaOH 🡪 3 Na2SO3 + 2 Al(OH)3

a) If you start with 389.4 g of Al2(SO3)3 and you isolate 212.4 g of Na2SO3, what is your percent yield for this reaction?

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Answer 1

Percent yield for this reaction ;

$=89.73\%$