Question

Carbon monoxide and oxygen react in the following manner:

2 CO _(g) + O_2 (g) → 2 CO_2 (g)

Information on the reaction is given in the table below:

[CO] 0.020 M, 0.040 M , 0.020 M , 0.011 M , 0.59 M , ♥

[O₂] 0.020 M , 0.020 M, 0.040 M , 1.22 M , ♣ , 0.59 M

Rate 3.68 x 10^-5 M/min , 1.47 x 10^-4 M/min, 7.36 x 10^-5 M/min , ♠ , 8.62 x 10^-3 M/min , 8.62 x 10^-3 M/min

Part A

Determine the order of the reaction with respect to CO.

Part B

Determine the order of the reaction with respect to O_2.

Part C

Calculate "k".

Part D

Calculate ♠.

Part E

Calculate ♣.

Part F

Calculate ♥.

Answer 1

Part A

Rate=$8.9\times 10^4[0.020M]^3[0.040M]$

$=0.0285M/min$

Part B

$=8.9\times 10^4[0.020M]^3[1.44M]$

$=1.025M/min$

Part C

$k=0.0285$ $M\over min$ $=k(0.020M)^3(0.040M)$

$k=$ ${{0.0285}M\over min}\over (0.020M)^3 (0.040M)$

$=8.9\times 10^4$ $M^3\over min$

Part D

$1\over 4$ $\times 0.0285M/min$ $=7.125\times 10^{-3} M/min$

Part E

$O_2=$ $0.020M\over 1.4min$ $=0.0143M/min$

Part D

$CO_2=$ $0.040M\over 1.4min$ $=0.0285M/min$