Question

ASAP PLZ

8.0 mL of 0.10 M HCl is titrated with 0.10 M NaOH. Perform the following calculations

Find the following and show all calculation workout

-pH of the acid before any NaOH is added

-Volume of 0.10 M NaOH needed to reach the equivalence point

-pH at the equivalence point

Answer 1

- $pH=-log[H^+]$

$pH=-log[0.10]$ $=1$

- The equation for the reaction is;

$NaOH_{(aq)}+HCl_{(aq)}\to NaCl_{(aq)}+H_2O_{(l)}$

Mole ratio$=1:1$

$\therefore$ Volume of $NaOH=8.0 ml$

- $pH=-log[H^+]$

$pH=-log[0.10]$ $=1$