Question

If the reaction gives 64% yield, how many grams oh PH3 should be used to give an actual yield of 250 grams of P2O5?

Answer 1

Percent of yield =( observed yield of product/theoretical yield of product)*100

Using this formula ,we can calculate the amount of PH3 used= (64*250/100)=160g

Hence 160g of PH3 required