Question

A quantity of electricity liberates 3.6g of silver from it's salt. What mass of alluminium will be liberated from it's salt by the same quantity of electricity?

Answer 1

If 108g of Ag = 95600C

3.6g of Ag =

$\frac{(95600 × 3.6)}{ 108} = 3217°C$ (nearest whole number)

27g of aluminum = 286800C

Xg of aluminum = 3217C

$\frac{27× 3217} { 286800 }= 0.30g$