1. What is the heat (q) needed by water with molar heat of vaporization of 40.7 kJ if it is 50.0 g in mass and boils at 100°C? Note that the molar mass of water is 18.0 g/mol.
2. How will you compare it with the heat needed by alcohol with molar heat of vaporization 44.0 kJ at 35.0 g and boils at 82.5°C? Note that the molar mass of isopropyl alcohol is 60.1 g/mol.
1.Let molar heat of vaporization be ∆Hvap
∆Hvap = 40.7 kJ
2.Moles of "H2O = \\frac{50}{18}=2.78 moles"
Heat = "40.7 \u00d7 2.78=113.146 kJ"
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