Question

You are performing an experiment that requires 5.22 M hydrochloric acid. You have a bottle of hydrochloric acid which is labeled as 7.50 M hydrochloric acid. If you use 1.54 L of the hydrochloric acid from this bottle to make the diluted solution for your experiment, what will the final volume of the diluted solution be?

Answer 1

$V_1=1.54L$

$M_1=7.50M$

$M_2=5.22M$

$M_1V_1=M_2V_2$

$V_2=\frac{7.5\times1.54}{5.22}=2.2L$