if you want to put 60.0L of Hydrogen gas at SATP into a bottle by reacting excess aluminium metal with sodium hydroxide solution, what mass of NaOH is required?
2NaOH +2AL + 2H2O =2NaALO2+3H2
1 Mole of hydrogen gas at STP=22.4L
60L=(60/22.4)=2.679
The mole ratio of NaOH:H2=2:3
2:3=1.786:2.679
The mass of NaOH required=1.786x40=71.44 grams
Comments
Leave a comment