2na3Po4+3MgCl2 -> 6NaCl+ Mg(Po4)2
We have given the reaction,
"3MgCl_2(aq)+2{Na}_3PO_4(aq) \\rightarrow Mg_3(PO_4)_2(s) + 6NaCl(aq)"
We can also write the ionic equation of this reaction.
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