Question #181833

The composition of N2O5 follows first-order kinetics based on the reaction below.

2N2O5 (g) → O2 (g) + 4NO2 (g)


The rate constant of the reaction at 25℃ is 3.46 × 10^3/s. How long (in seconds) would it take for an initial concentration of 0.050 M to decrease to 0.015 M? What is the half-life of the reaction?


Expert's answer

Change in concentration = 0.0500.015=0.035M0.050- 0.015= 0.035M


T=0.0353.46×103=1.12×105secT = \frac{0.035}{3.46×10^{3}}=1.12×10^{-5} sec



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