Question

How many grams of ice at 0°c could be melted by the addition of 2.25 kj of heat?

Answer 1

solution:-

Given

Temperature = 0^oC

Heat = 2.25k j

Mass= ?

So

By using

$\Delta Q = mL_{fusion \space of \space ice}$

$\Delta Q$ = heat = 2.25 kilo joule = 537.7629 gram calorie

m = mass

$L_{fusion \space of \space ice}$ = latent heat of fusion of ice = 80 cal/gm

By putting values in formula

m = $\Delta Q \over L_{fusion \space of \space ice}$

m = $537.7629 \over 80$

Answer

$\boxed{m = 6.72203625 gram}$