Answer to Question #181690 in General Chemistry for Sall

Question

Calculate the number of atoms in 1.00 g of table sugar, C₁₂H₂₂O₁₁

CCalculate the number of carbon atoms in 1.00 g of table sugar

Answer 1

n (C₁₂H₂₂O₁₁) = m(C₁₂H₂₂O₁₁)/M(C₁₂H₂₂O₁₁)

n_molec= n(C₁₂H₂₂O₁₁)*N_A

n_at= n_molec*45

n_at(C)= n_molec*12

n_molec= m(C₁₂H₂₂O₁₁)/M(C₁₂H₂₂O₁₁) * N_A = 1g / 342g/mol * 6.022*10²³molec/mol = 1.76*10²¹ molec

n_at = 1.76*10²¹*45= 7.92*10²²

n_at(C) = 1.76*10²¹*12= 2.11*10²²

Answer: 7.92*10²² atoms, 2.11*10²² carbon atoms