Answer to Question #181580 in General Chemistry for csf

Question

8.0 mL of 0.10 M HCl is titrated with 0.10 M NaOH. Perform the following calculations (7 points):

1. pH of the acid before any NaOH is added
2. Volume of 0.10 M NaOH needed to reach the equivalence point
3. pH at the equivalence point

8.0 mL of 0.10 M HC2H3O2 is titrated with 0.10 M NaOH. Perform the following calculations

1. pH of the acid before any NaOH is added
2. Volume of 0.10 M NaOH needed to reach the equivalence point
3. pH at the equivalence point
4. Volume of 0.10 M NaOH needed to reach the half-way point
5. pH at the half-way point

8.0 mL of 0.10 M NH3 is titrated with 0.10 M HCl. Perform the following calculations

1. pH of the base before any HCl is added
2. Volume of 0.10 M HCl needed to reach the equivalence point
3. pH at the equivalence point
4. Volume of 0.10 M HCl needed to reach the half-way point
5. pH at the half-way point

Answer 1

pH of the acid before any NaOH is addedi is

$PH = -log (0.10)=1$

Volume of 0.10 M NaOH needed to reach the equivalence point= $0.04398 L$

pH = 7.00