Answer to Question #181214 in General Chemistry for Marcus Snearley

Question

What is the volume of 6.00 M nitric acid that contains 6 302 g of HNO 3 solute (63.02g / m * o * l) ?

Answer 1

First wee need to find the moles of HNO3 in 6302g

We know that;

Moles $= \dfrac{mass}{molar mass} = \dfrac{6302g}{63.02g/mol}$

= 100mol

We also know that;

Molarity $= \dfrac{moles}{Volume (L)}$

Therefore;

Volume (L) $=\dfrac{mol}{Molarity} = \dfrac{100mol}{6.00mol/L}$

= 16.667 L