Question

A student starts with s 18.0 M solution of H₂SO₄. How many ml would be required to produce 235 ml of a 1.77 M H₂SO₄ solution?

Answer 1

From the equation;

$M1V1=M2V2$

Where;

$M1( original concentration)=18.0M$

$V1(Initial volume)=unknown$

$M2(Final concentration)=1.77M$

$V2(Final volume)=235ml$

$\therefore$ $V1=$ $M2V2\over M1$

$V1=$ $1.77M\times235ml\over18M$ $=23.11ml$

Initial volume$=23.11 ml$