Question #181163

How many grams of CaCl2 would be required to produce a .750 M solution with a 855 ml volume?


1
Expert's answer
2021-04-14T06:09:52-0400

Moles=0.750×8551000=0.64molesMoles = 0.750 × \frac{855}{1000}=0.64 moles


Grams=0.64×110.98=71.03gGrams = 0.64 × 110.98= 71.03 g



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