calculate the number of moles of sodium oxide that should be produced when 26.50 grams of sodium metal reacts with oxygen gas
4Na+O2=2Na2O
n(Na)=m(Na)/M(Na)= 26.50g / 23g/mol = 1.152 mol
n(Na2O)= n(Na)/2 = 1.152mol/2= 0.576 mol
Answer: 0.576 mol Na2O
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