Question

You mix 55.0 mL of 0.10 M HCl and 110.0 mL of 0.050 M NH3. What is the pH of the resulting solution? Provide your solution.

Answer 1

Molarity of HCl = 0.1

Moles of H⁺= molarity of HCl × volume of sample

= 0.055L × 0.1. = 5.5 × 10^-3

Moles of OH^- = molarity of NH₃ × Volume of sample

= 0.11 × 0.050

= 5.5 × 10^-3

= (5.5 × 10^-3) /5.5 × 10^-3

= 1

= 1/0.165 = 0

PoH= -log(6.1)

= -0.77

= 14--0.77

PH= 14.77