A solution is prepared by dissolving 5.00g of NaOH in 150 g of water. What is the molality of the solution?
Moles of NaOH =5.0040=0.125moles=\frac{5.00}{40}=0.125moles=405.00=0.125moles
Molarity =0.125150×10−3=0.83M= \frac{0.125}{150×10^{-3}}=0.83 M=150×10−30.125=0.83M
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