Calculate the pH of the following acid or base.
1. 3.6 x 10-7 M HNO3
2. 2.0 x 10-4 M NaOH
1.pH=−log(3.6×10−7)pH =-log (3.6×10 ^{-7})pH=−log(3.6×10−7)
pH=6.4pH =6.4pH=6.4
2.pH=−log(2.0×10−4)pH =-log(2.0×10 ^{-4})pH=−log(2.0×10−4)
pH=3.7pH=3.7pH=3.7
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