Question

The proof of an alcoholic beverage is twice the volume percent of ethyl alcohol, C₂H₅OH. For an 80.0 proof rum, what is the molality of ethyl alcohol if D _C2H5OH = 0.789g/ml and MM = 46.08 g/mol.

Answer 1

Moles = $0.789×46.08=36.36moles$